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-.0002x^2+4.487x+2=0
We add all the numbers together, and all the variables
-0.0002x^2+4.487x+2=0
a = -0.0002; b = 4.487; c = +2;
Δ = b2-4ac
Δ = 4.4872-4·(-0.0002)·2
Δ = 20.134769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.487)-\sqrt{20.134769}}{2*-0.0002}=\frac{-4.487-\sqrt{20.134769}}{-0.0004} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.487)+\sqrt{20.134769}}{2*-0.0002}=\frac{-4.487+\sqrt{20.134769}}{-0.0004} $
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